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permutation /combination problem

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Junior | Next Rank: 30 Posts
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by eyoussef » Tue May 19, 2009 12:13 am
can somebody please help me with the below problem:


"How many 5 letter initials can be formed using alphabet of the english language that contain 2 distinct vowels and 3 distinct consonants"
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by dumb.doofus » Tue May 19, 2009 12:46 am
5c2*21c3 = 13300
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by scoobydooby » Tue May 19, 2009 1:14 am
different positions of the vowels/consonants would give rise to different initials. so total number of initials would be

5c2*21c3*5! = 13300*120=1596000
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by Svedankae » Tue May 19, 2009 1:14 am
is that correct? i got 159,600
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