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by ST » Mon Mar 30, 2009 9:57 am
anyone can help me solve this problem?
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by rs2010 » Mon Mar 30, 2009 10:57 am
This is easy one and you might missed the statement that numbers are consecutive.

So 9 numbers can be written as

x, x+1....x+8

Let me tell you easier way to tell such type of prob for PS

assume numbers as

x-4,x-3, x-2, x-1, x, x+1, x+2, x+3, x+4 so that when you need to sum it you will get only 9x=9*7

x=7 so you can get 10th and 11th one as 7+5, 7+6 sum=25

Same holds true for B so ans D
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