BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

x ≠ ±1

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
User avatar
GMAT Instructor
Posts: 3650
Joined: Wed Jan 21, 2009 4:27 amFollowed by: 80 members
Location: India
Thanked: 267 times
GMAT Score:760
by sanju09 » Wed Mar 10, 2010 1:47 am
(∣x∣ + 1)/(∣x∣ - 1) < 4; x ≠ ±1.

What is the solution to the above inequality?
(A) x < -5/3, -1 < x < 1
(B) x < -5/3, -1 < x < 1, x > 5/3
(C) -1 < x < 1, x > 5/3
(D) -5/3 < x < 5/3
(E) 0 < x < 5/3
The mind is everything. What you think you become. -Lord Buddha



Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
User avatar
Legendary Member
Posts: 1560
Joined: Tue Nov 17, 2009 2:38 amFollowed by: 5 members
Thanked: 137 times

by thephoenix » Wed Mar 10, 2010 3:19 am
sanju09 wrote:(∣x∣ + 1)/(∣x∣ - 1) < 4; x ≠ ±1.

What is the solution to the above inequality?
(A) x < -5/3, -1 < x < 1
(B) x < -5/3, -1 < x < 1, x > 5/3
(C) -1 < x < 1, x > 5/3
(D) -5/3 < x < 5/3
(E) 0 < x < 5/3
IMO A

all values of option a satisfies the eqn
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
GMAT Instructor
Posts: 3650
Joined: Wed Jan 21, 2009 4:27 amFollowed by: 80 members
Location: India
Thanked: 267 times
GMAT Score:760

by sanju09 » Wed Mar 10, 2010 3:40 am
thephoenix wrote:
sanju09 wrote:(∣x∣ + 1)/(∣x∣ - 1) < 4; x ≠ ±1.

What is the solution to the above inequality?
(A) x < -5/3, -1 < x < 1
(B) x < -5/3, -1 < x < 1, x > 5/3
(C) -1 < x < 1, x > 5/3
(D) -5/3 < x < 5/3
(E) 0 < x < 5/3
IMO A

all values of option a satisfies the eqn
[spoiler]A ≠ OA[/spoiler]
The mind is everything. What you think you become. -Lord Buddha



Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Master | Next Rank: 500 Posts
Posts: 102
Joined: Sat Feb 20, 2010 5:38 am
Location: IIM Ahmedabad
Thanked: 10 times

by firdaus117 » Wed Mar 10, 2010 3:49 am
Case 1 mod x-1>0
which means x>1 and x<-1
i.e. -1>x>1 -------- (1)
Multiply both sides by mod x-1,
mod x +1 < 4(mod x-1)
3mod x > 5
mod x>5/3
-5/3>x>5/3 ----------(2)
Combining 1 and 2,permissible values of x will lie in interval
-5/3>x>5/3 --------------(3)
Case 2 mod x-1<0
i.e. -1<x<1 -----------------(4)
Multiply both sides by mod x-1,
mod x +1 > 4(modx-1) [the sign of inequality reverses as we are multiplying by a negative quantity]
-5/3<x<5/3 ------------(5)
Combining 4 and 5,
-1<x<1------------------(6)
Finally combining 3 and 6,we get final result as:
[spoiler]x < -5/3, -1 < x < 1, x > 5/3 Option B[/spoiler]
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
GMAT Instructor
Posts: 3650
Joined: Wed Jan 21, 2009 4:27 amFollowed by: 80 members
Location: India
Thanked: 267 times
GMAT Score:760

by sanju09 » Sat Mar 13, 2010 3:31 am
firdaus117 wrote:Case 1 mod x-1>0
which means x>1 and x<-1
i.e. -1>x>1 -------- (1)
Multiply both sides by mod x-1,
mod x +1 < 4(mod x-1)
3mod x > 5
mod x>5/3
-5/3>x>5/3 ----------(2)
Combining 1 and 2,permissible values of x will lie in interval
-5/3>x>5/3 --------------(3)
Case 2 mod x-1<0
i.e. -1<x<1 -----------------(4)
Multiply both sides by mod x-1,
mod x +1 > 4(modx-1) [the sign of inequality reverses as we are multiplying by a negative quantity]
-5/3<x<5/3 ------------(5)
Combining 4 and 5,
-1<x<1------------------(6)
Finally combining 3 and 6,we get final result as:
[spoiler]x < -5/3, -1 < x < 1, x > 5/3 Option B[/spoiler]
Good to see that the OA is matched somehow, the discontinued intervals must not be shown as continuous. Any better explanation to this peculiar problem that only a very few would find on GMAT?
The mind is everything. What you think you become. -Lord Buddha



Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Master | Next Rank: 500 Posts
Posts: 102
Joined: Sat Feb 20, 2010 5:38 am
Location: IIM Ahmedabad
Thanked: 10 times

by firdaus117 » Sat Mar 13, 2010 6:20 am
sanju09 wrote: Good to see that the OA is matched somehow, the discontinued intervals must not be shown as continuous. Any better explanation to this peculiar problem that only a very few would find on GMAT?
Totally agree!But I got too bored typing all that stuff and missed x is not equal to -1 and +1.It's better to solve such question by drawing number line representing different points of discontinuity.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1