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Re: GCD question

by Vemuri » Sun Jun 14, 2009 9:50 pm
tohellandback wrote:
A) agreed as you said

B) take the example x=21,y=14
35x=5*7*3*7
20y=4*5*2*7
GCF is 5*7 (7 is 21-14, thats what I meant when i said "depends upon the values of x and y")
C) Hold on I will give you a "big explanation"

D) possible because it is possible that between two numbers one of them can be the GCF.
I will give you an example, you figure out the rest.
y=3
=12
well, let me explain
since 20y contains 2^2, 5 and y. it can be the GCF if 35x contains all of these. now 35x already has 5 so, any value of x that contains 2^2 and as factors will make it possible

E) same explanation as above
20y already contains 5. so any value of y that has x and 7 as factors will make it possible
ex: x=3
y=21

by now I think you have understood why C is right, but still
35x=5*7*x
20x would have been possible only if there was a 2^2 in the factorization.
now you can argue that what if x has that 2^2 so precious to me
let x=4
now 20x is 2^2*5*2^2
but you original number 35x doesn't have two (2^2)s. It has only one 2^2 and that is from x. so 20x cannot divide it. Now you see why i mentioned there should be the prime numbers in the factorization.

Hope I am clear. Thanks
Yep, I guess I had a temporary mind block & got completely stuck. Only 20x CANNOT be a divisor of 35x & 20y, because 35x/20x is not an integer.

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by axat » Mon Jun 15, 2009 12:58 am
If 6xy = (x)square(y) + 9y, what is the value of xy?

(1) x = –2

(2) x < 0



Source : MGMAT

OA will follow. I know this is a DS question posted in the PS section, but I don't want start a different thread for the DS questions.

In this question, I'll appreciate it if you guys could tell me what is it that went through your minds as you solved this question.

My instinct was to solve the equation by eliminating y, which is what I did, but that gave me a value for x and left me stranded.
Last edited by axat on Mon Jun 15, 2009 1:10 am, edited 1 time in total.

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by tohellandback » Mon Jun 15, 2009 1:01 am
axat wrote:If 6xy = x2y + 9y, what is the value of xy?

(1) x = –2

(2) x < 0



Source : MGMAT

OA will follow. I know this is a DS question posted in the PS section, but I don't want start a different thread for the DS questions.

In this question, I'll appreciate it if you guys could tell me what is it that went through your minds as you solved this question.

My instinct was to solve the equation by eliminating y, which is what I did, but that gave me a value for x and left me stranded.
is that x^2*y or x*2*y
The powers of two are bloody impolite!!

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by axat » Mon Jun 15, 2009 1:21 am
Sorry. The vagaries of copying and pasting. Edited the question.

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by tohellandback » Mon Jun 15, 2009 1:50 am
axat wrote:If 6xy = (x)square(y) + 9y, what is the value of xy?

(1) x = –2

(2) x < 0



Source : MGMAT

OA will follow. I know this is a DS question posted in the PS section, but I don't want start a different thread for the DS questions.

In this question, I'll appreciate it if you guys could tell me what is it that went through your minds as you solved this question.

My instinct was to solve the equation by eliminating y, which is what I did, but that gave me a value for x and left me stranded.
I seriously hate these kind of questions because I believe they are something not gmat standard. Also, on the forum I have encountered such a question before and we could not reach a final solution. It was something with square roots with x=0 already provided.

anyways the best I could come up with this and with this question I hope we find out what is the right solution
IMO D

6xy = x^2*y + 9y
I thought of eliminating y too, but it leads us to nowhere
so y(x^2-6x+9)=0
or y(x-3)^2=0
now either y=0 or x=3

1)x=-2, x can only be 3. so I assume that x=-2 is not possible.(this is where I have a problem. It is given a fact, should I ignore it?)
so y must be 0
xy=0. sufficient

2) x<0. same reason . not possible
xy=0
Sufficient

I am waiting for other answers
Thanks
The powers of two are bloody impolite!!

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by Vemuri » Mon Jun 15, 2009 3:18 am
axat wrote:If 6xy = (x)square(y) + 9y, what is the value of xy?
(1) x = –2

(2) x < 0
How are we to interpret the statement in the question? Is it 6xy = (x^2)*y + 9y or 6xy = (x^2y) + 9y?

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by ssmiles08 » Mon Jun 15, 2009 5:17 am
LOL yes I too, like you guys tried eliminating y...and of course that got me no where as well.

Ditto to tohellandback. I did the same thing.

bring 6xy over to the other side. x^2y - 6xy + 9y = 0.

y(x^2 - 6x +9) = 0. y(x-3)(x-3) = 0

The only value for y is 0. So any x which is multiplied to y always = 0.

I don't know...I just find this question odd b/c you don't really need any of the 2 options to figure out the value of xy. (D)

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by axat » Mon Jun 15, 2009 7:46 am

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by axat » Mon Jun 15, 2009 7:49 am
Source MGMAT

Eighty percent of the lights at Hotel California are switched on at 8 p.m. one evening. However, forty percent of the lights that are supposed to be switched off are actually switched on, and ten percent of the lights that are supposed to be switched on are actually switched off. What percent of the lights that are switched on are supposed to be switched off?


A 22(2/9)%
B 16(2/3)%
C 11(1/9)%
D 10%
E 5%

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by DarkKnight » Mon Jun 15, 2009 7:26 pm
Suppose total # of lights is 100. Also,
X=# of lights supposed to be switched on
Y=# of lights supposed to be switched off
Hence we get,
20=0.1X + 0.6Y..............1)
80=0.9X + 0.4Y..............2)
Multiply eqn. 1) by 4 and cancel the terms. We get 2Y=0.5X. This gives us X=4Y.......................3)

Now percentage of lights supposed to be turned off from the # of lights that are on is given by:

0.4Y/0.8(X+Y) = Y/2(X+Y). Substituting value of eqn. 3) here we get, Y/2(5Y)=1/10 * 100=10%

Answer = 10%

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by axat » Thu Jun 18, 2009 6:16 am
A breakfast that consists of 1 ounce of corn puffs and 8 ounces of fruit X provides 257 calories. When 8 ounces of fruit Y is substituted for the 8 ounces of fruit X, the total number of calories is reduced to 185. If fruit X provides 1.8 times as many calories as fruit Y, how many calories does 8 ounces of fruit Y alone provide ?

(A) 11.25
(B) 72
(C) 90
(D) 95
(E) 129.6


I spent over 3 minutes on this question, and yet I couldn't get an answer, so tell how would you have answered this in under 100 seconds. Do elaborate on the method. I have a feeling plugging in the numbers will work best.

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by tohellandback » Thu Jun 18, 2009 6:49 am
IMO C, and well i did it in <40 secs:)
so 1C+8X=257
1C+8Y=185
subtract 2 drom 1

8x-8y=72
8*1.8*y-8y=72
6.4y=72
y=72/6.4
we need to find 8y
so 8y=(72*8)/6.4==90
The powers of two are bloody impolite!!

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by axat » Thu Jun 18, 2009 6:56 am
tohellandback wrote:IMO C, and well i did it in <40 secs:)
so 1C+8X=257
1C+8Y=185
subtract 2 drom 1

8x-8y=72
8*1.8*y-8y=72
6.4y=72
y=72/6.4
we need to find 8y
so 8y=(72*8)/6.4==90

I am too embarrassed to even SHARE the stupid mistake I made. My approach was exactly the same as yours but I made an error that is reserved for those who are exclusively thick in the head.

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by tohellandback » Thu Jun 18, 2009 7:21 am
axat wrote:
tohellandback wrote:IMO C, and well i did it in <40 secs:)
so 1C+8X=257
1C+8Y=185
subtract 2 drom 1

8x-8y=72
8*1.8*y-8y=72
6.4y=72
y=72/6.4
we need to find 8y
so 8y=(72*8)/6.4==90

I am too embarrassed to even SHARE the stupid mistake I made. My approach was exactly the same as yours but I made an error that is reserved for those who are exclusively thick in the head.
you have no idea how thick i can get sometimes.. :roll:
The powers of two are bloody impolite!!

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by dumb.doofus » Thu Jun 18, 2009 7:58 pm
axat wrote:Source MGMAT

Eighty percent of the lights at Hotel California are switched on at 8 p.m. one evening. However, forty percent of the lights that are supposed to be switched off are actually switched on, and ten percent of the lights that are supposed to be switched on are actually switched off. What percent of the lights that are switched on are supposed to be switched off?


A 22(2/9)%
B 16(2/3)%
C 11(1/9)%
D 10%
E 5%
My approach is similar to one given by darkknight.. I felt that mine was one step short.. I think that you dont need two equations.. so posting the solution here.. post may seem long coz I am elaborating all steps..

Let X be the number of lights supposed to be off
Let Y be the number of lights supposed to be on..

1. Eighty percent of the lights at Hotel California are switched on at 8 p.m.

This implies 80%(X+Y) are ON --------------- (1)

2. Forty percent of the lights that are supposed to be switched off are actually switched on

This implies 40%X are ON ----------------- (2)

3. ten percent of the lights that are supposed to be switched on are actually switched off

This implies 90% of Y are ON ----------- (3)

Essentially (1) = (2) + (3)
0.8(X+Y) = 0.4X + 0.9Y
This gives 4X = Y

and all we have to find is : What percent of the lights that are switched on are supposed to be switched off?

This is essentially (2)/(1)

Substitute 4X = Y in that and you get 10%
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