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Last edited by nandansingh on Fri Oct 31, 2008 9:49 am, edited 1 time in total.
Student, ISB Co2010
total number of factors of k = 6
prime factors of k = 3,7
for total to be 6 factors there can be two cases
Case I
3^2 * 7 , no. of factors = (2+1)*(1+1) = 6
Case II
3* 7^2, no. of factors = (1+1) * (2+1) = 6
Statement I
3 ^ 2 is a factor of k, therefore, k has to be 3^2 * 7 = 63
Sufficient.
Statement II
7 ^ 2 is not a factor of k, therefore, k has to be 3^2 * 7 = 63.
Sufficient.
Hence D.
Let me know if you still have any doubts.
