hemant_rajput wrote:Q5 . A and B walk up an escalator. The escalator moves at a constant speed. A takes six steps for every four of B's step. A gets to the top of the escalator after having taken 50 steps , while B( Slower) takes only 40 steps to reach the top. If the escalator were turned off, how many steps would they have to take to walk up?
a. 80
b. 100
c. 120
d. 160
[spoiler]oa : b[/spoiler]
A = A's rate, B = B's rate, and E = the escalator's rate.
B/E = B/A * A/E.
Since B travels 4 steps for every 6 steps that A travels:
B/A = 4/6 = 2/3.
We can plug in the answers, which represent the number of steps on the escalator.
Answer choice C: 120 steps
Since A travels 50 steps to reach the top, the escalator must travel 70 steps, for a total of 50+70 = 120 steps.
Thus:
A/E = 50/70 = 5/7.
B/E = B/A * A/E = 2/3 * 5/7 = 10/21 = 40/84.
Since B/E = 40/84, when B travels 40 steps to reach the top, the escalator travels 84 steps, for a total of 40+84 = 124 steps.
Not possible: the escalator contains only 120 steps.
Since the total number of steps traveled by B and the escalator must DECREASE, the correct answer must be SMALLER.
Eliminate C.
Answer choice B: 100 steps
Since A travels 50 steps to reach the top, the escalator must travel 50 steps, for a total of 50+50 = 100 steps.
Thus:
A/E = 50/50 = 1/1.
B/E = B/A * A/E = 2/3 * 1/1 = 2/3 = 40/60.
Since B/E = 40/60, when B travels 40 steps to reach the top, the escalator travels 60 steps, for a total of 40+60 = 100 steps.
Success!
The correct answer is
B.
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