is it 24?
1 coin can go to any of 6 pockets...= 6
2 coin can go to any of 6 pockets...= 6
3 coin can go to any of 6 pockets...= 6
4 coin can go to any of 6 pockets...= 6
24
Combination
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Only 4 pockets are needed for putting 4 coins.JeetGulia wrote:A boy has 6 different pockets and 4 different coins. In how many ways can he put these coins in pockets.
a)1296
b)4096
c) 24
d) 10
e) 240.
picking 4 pockets from 6 pockets = 6c4 = 15 ways.
Now, out of these 4,
each pocket can be filled in 4 ways.
total number of ways here = 4*4 = 16.
Hence Total = 16*15 = 240 ways.
Whats the OA?
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There are 6 diff pockets and 4 diff coins. SInce more than one coin can go to one pocket we will have 6^4 = 1296.
I think A.
I think A.
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Very nice question. Here's my approach:JeetGulia wrote:A boy has 6 different pockets and 4 different coins. In how many ways can he put these coins in pockets.
a)1296
b)4096
c) 24
d) 10
e) 240.
For every counting question, I always ask, "Can I take the task and break it into stages?"
Here, the answer is yes.
Stage 1: Place coin #1 in one of the 6 pockets.
Stage 2: Place coin #2 in one of the 6 pockets.
Stage 3: Place coin #3 in one of the 6 pockets.
Stage 4: Place coin #4 in one of the 6 pockets.
Then determine the number of ways to accomplish each stage.
Stage 1: 6 ways (place in pocket 1, 2, 3, 4, 5, or 6)
Stage 2: 6 ways (place in pocket 1, 2, 3, 4, 5, or 6)
Stage 3: 6 ways (place in pocket 1, 2, 3, 4, 5, or 6)
Stage 4: 6 ways (place in pocket 1, 2, 3, 4, 5, or 6)
By the Fundamental Counting Principle, we can find the number of ways to complete the entire task by multiplying the number of ways to accomplish each stage.
So, total = 6x6x6x6 =6^4 ways (aka 1296 ways)
Answer = A













