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by thephoenix » Thu May 13, 2010 2:09 am
pqr is 145
and q is 4
p!=1!=1
q!=4!=24
r!=5!=120
total=145
hence q is 4
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by mitaliisrani » Thu May 13, 2010 2:16 am
thephoenix wrote:pqr is 145
and q is 4
p!=1!=1
q!=4!=24
r!=5!=120
total=145
hence q is 4[/quote


Hey thanks but can you tell me your approach to this sum as in how you thought of the number to be 145
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by mitaliisrani » Thu May 13, 2010 2:24 am
thephoenix wrote:pqr is 145
and q is 4
p!=1!=1
q!=4!=24
r!=5!=120
total=145
hence q is 4
Hey thanks but can you tell me your approach to this sum as in how you thought of the number to be 145
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by thephoenix » Thu May 13, 2010 2:26 am
mitaliisrani wrote:
thephoenix wrote:pqr is 145
and q is 4
p!=1!=1
q!=4!=24
r!=5!=120
total=145
hence q is 4
Hey thanks but can you tell me your approach to this sum as in how you thought of the number to be 145
my approach was hit and trial
Many of the great achievements of the world were accomplished by tired and discouraged men who kept on working
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by gmatmachoman » Thu May 13, 2010 6:44 am
thephoenix wrote:
mitaliisrani wrote:
thephoenix wrote:pqr is 145
and q is 4
p!=1!=1
q!=4!=24
r!=5!=120
total=145
hence q is 4
Hey thanks but can you tell me your approach to this sum as in how you thought of the number to be 145
my approach was hit and trial
I did backsolving!!I am eager to see some algerbraic approach!
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