If each of the digits can be used, as many times as necessary, what is the probability of creating a three-digit number with three consecutive even digits in order from left to right?
even digit=0,2,4,6,8
3 consecutive even digits are 1st--->0,2,4 ; 2nd---->2,4,6;3rd---->4,6,8;
for 1st set tot # can be formed in 2*3*3=18 ways
for 2nd set tot # can be formed in 3^3=27 ways
for 3rd set tot # can be formed in 3^3=27 ways
tot=18+27+27=72
wats the ans
