From a total of 5 boys and 4 girls, how many 4-person

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From a total of 5 boys and 4 girls, how many 4-person committees can be selected if the committee must have exactly 2 boys and 2 girls?

A. 16
B. 24
C. 60
D. 120
E. 240

The OA is C.

I solved this PS question as follows,

2 boys can be selected from 5 boys in 5C2 ways = 10 ways
2 girls can be selected from 4 girls in 4C2 ways = 6 ways

Hence total number of ways = 10 * 6 = 60 ways.
Hence option C.

Can anyone explain another way to solve this question, please? Thanks!
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by Jay@ManhattanReview » Sun Apr 15, 2018 8:44 pm
BTGmoderatorLU wrote:From a total of 5 boys and 4 girls, how many 4-person committees can be selected if the committee must have exactly 2 boys and 2 girls?

A. 16
B. 24
C. 60
D. 120
E. 240

The OA is C.

I solved this PS question as follows,

2 boys can be selected from 5 boys in 5C2 ways = 10 ways
2 girls can be selected from 4 girls in 4C2 ways = 6 ways

Hence total number of ways = 10 * 6 = 60 ways.
Hence option C.

Can anyone explain another way to solve this question, please? Thanks!
This is all fine. :)

-Jay
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by Jeff@TargetTestPrep » Tue Apr 17, 2018 3:28 pm
BTGmoderatorLU wrote:From a total of 5 boys and 4 girls, how many 4-person committees can be selected if the committee must have exactly 2 boys and 2 girls?

A. 16
B. 24
C. 60
D. 120
E. 240
We can select 2 girls in 4C2 = (4 x 3)/2! = 6 ways.

We can select 2 boys in 5C2 = (5 x 4)/2! = 10 ways.

So the group can be formed in a total of 6 x 10 = 60 ways.

Answer: C

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Head of GMAT Instruction
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