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The figure shows the quadratic function y = x2 and the points D and G on the graph. The coordinate of point A is (0, 9)

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by Max@Math Revolution » Wed Jun 03, 2020 3:03 am

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[GMAT math practice question]

The figure shows the quadratic function y = x^2 and the points D and G on the graph. The coordinate of point A is (0, 9), and ABCD and BEFG are squares. What is the difference between the area of ABCD and that of BEFG?
6.3ps.png
A. 1
B. 2
C. 3
D. 4
E. 5
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Re: The figure shows the quadratic function y = x2 and the points D and G on the graph. The coordinate of point A is (0

by Max@Math Revolution » Fri Jun 05, 2020 12:29 am
=>

Since the coordinate of point A is (0, 9), we have D(3, 9), B(6, 0)
and G(√6, 6).
Then the length of the sides of square ABCD is 3, and that of sides of the square BEFG is √6.
The difference between areas of the two squares is 3^2 - (√6)^2 = 9 - 6 = 3.
Therefore, C is the answer.
Answer: C
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