lheiannie07 wrote:Pam and Robin each roll a pair of fair, six-sided dice. What is the probability that Pam and Robin will both roll the same set of two numbers?
A. 1/216
B. 1/36
C. 5/108
D. 11/216
E. 1/18
We need to determine the probability that when Pam and Robin each rolls a pair of fair, six-sided dice, they both roll the same set of numbers. There are two scenarios: when Pam and Robin both roll the same two numbers and when they roll two distinct numbers.
Scenario 1: When the two numbers on the dice are the same
Let's say they both roll 1s. That is, Pam rolls (1, 1) and Robin rolls (1, 1). The probability of this happening is
1/6 x 1/6 x 1/6 x 1/6 = 1/(6^4)
Since the probability is the same for all 6 pairs of numbers, the probability of their rolling the same numbers is 6 x 1/(6^4) = 1/(6^3) = 1/216.
Scenario 2: When the two numbers on the dice are distinct
There are 6 x 5 = 30 ways to roll two distinct numbers when rolling two dice.
Let's say Pam rolls (1, 2) and Robin also rolls (1, 2). The probability of this happening is:
1/6 x 1/6 x 1/6 x 1/6 = 1/(6^4)
However, if Pam rolls (1, 2) and Robine rolls (2,1), those are still considered the same set of numbers, and the probability of that occurring is also 1/(6^4).
Therefore, for each pair of distinct numbers rolled, the probability is 2 x 1/(6^4) = 2/(6^4). Since there are 30 such pairs, the overall probability is 30 x 2/(6^4) = 60/(^4) = 10/(6^3) = 10/216.
Finally, since the events in option 1 and those in option 2 are mutually exclusive, we use the addition rule of probability. That is, the probability that Pam and Robin will both roll the same set of two numbers is:
1/216 + 10/216 = 11/216
Answer:
D