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On a 20 mile course, Pat bicycled at an average rate of 30 miles per hour

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On a 20 mile course, Pat bicycled at an average rate of 30 miles per hour

by BTGModeratorVI » Sun Apr 05, 2020 8:57 am

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On a 20 mile course, Pat bicycled at an average rate of 30 miles per hour for the first 12 minutes and without a break, ran the rest of the distance at an average rate of 8 miles per hour. How many minutes did Pat take to cover the entire course?

A. 75
B. 105
C. 117
D. 150
E. 162

Answer: C
Source: GMAT paper tests
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Re: On a 20 mile course, Pat bicycled at an average rate of 30 miles per hour

by Jay@ManhattanReview » Sun Apr 05, 2020 10:11 pm
BTGModeratorVI wrote: ↑
Sun Apr 05, 2020 8:57 am
 On a 20 mile course, Pat bicycled at an average rate of 30 miles per hour for the first 12 minutes and without a break, ran the rest of the distance at an average rate of 8 miles per hour. How many minutes did Pat take to cover the entire course?

A. 75
B. 105
C. 117
D. 150
E. 162

Answer: C
Source: GMAT paper tests
Given that Pat bicycled at an average rate of 30 miles per hour for the first 12 minutes, he covered distance of (30/60)*12 = 6 miles

Thus, miles left to be covered = 20 – 6 = 14 miles

Thus, time taken to cover 24 miles = 14/8 hours = (14/8)*60 = 105 minutes

Total time taken = 105 + 12 = 117 minutes

The correct answer: C

Hope this helps!

-Jay
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Re: On a 20 mile course, Pat bicycled at an average rate of 30 miles per hour

by Scott@TargetTestPrep » Thu Apr 09, 2020 3:46 am
BTGModeratorVI wrote: ↑
Sun Apr 05, 2020 8:57 am
 On a 20 mile course, Pat bicycled at an average rate of 30 miles per hour for the first 12 minutes and without a break, ran the rest of the distance at an average rate of 8 miles per hour. How many minutes did Pat take to cover the entire course?

A. 75
B. 105
C. 117
D. 150
E. 162

Answer: C
Source: GMAT paper tests
Pat originally biked 30 x 12/60 = 6 miles.

So it took him 14/8 = 7/4 = 1 3/4 = 1 hour and 45 minutes = 105 minutes to run the remaining 14 miles.

So, in total, Pat took 12 + 105 = 117 minutes to complete the course.

Answer: C

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Re: On a 20 mile course, Pat bicycled at an average rate of 30 miles per hour

by Brent@GMATPrepNow » Thu Apr 09, 2020 5:40 am
BTGModeratorVI wrote: ↑
Sun Apr 05, 2020 8:57 am
 On a 20 mile course, Pat bicycled at an average rate of 30 miles per hour for the first 12 minutes and without a break, ran the rest of the distance at an average rate of 8 miles per hour. How many minutes did Pat take to cover the entire course?

A. 75
B. 105
C. 117
D. 150
E. 162

Answer: C
Source: GMAT paper tests
Let's start with a WORD EQUATION

(Distance traveled at 30 mph) + (Distance traveled at 8 mph) = 20 miles

Distance = (rate)(time)
Let t = the time (in hours) Pat spent running at 8 mph
Aside: 12 minutes = 1/5 hours

So, we get: (30 miles per hour)(1/5 hours) + (8 miles per hour)(t hours) = 20 miles
Simplify: 6 + 8t = 20
So: 8t = 14
t = 14/8 = 7/4 = 1.75 hours = 105 minutes

How many minutes did Pat take to cover the entire course?
Pat spent 12 minutes riding a bike, and 105 minutes running
TOTAL time = 12 + 105 = 117

Answer: C

Cheers,
Brent
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Re: On a 20 mile course, Pat bicycled at an average rate of 30 miles per hour

by deloitte247 » Thu Apr 09, 2020 10:14 pm
Total distance = 20 miles
Part of the total distance was covered by bicycle and the rest on foot.
On Bicycle;
Speed = 30 mph
Time = 12 minutes = 12/60 = 1/5 hours
Total distance covered with bicycle = speed * time
$$=30\cdot\frac{1}{5}=6miles$$
Therefore, the total distance covered by foot when running = total distance - distance covered with bicycle
distance covered by foot = 20 - 6 = 14 miles

Running on foot;
Speed = 8 miles per hour
Distance = 14 miles
Time taken = distance / speed = 14/8
= 1.75 hours

or

60 * 1.75 = 105mins

Total minutes taken to cover the total distance /entire course = time on bicycle + time used on foot
= 12 mins + 105 mins
= 117 mins

Answer = option C
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