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If a triangle in the \(xy\)-coordinate system has vertices at \((-2 , -3), (4, -3)\) and \((28, 7),\) what is the area

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If a triangle in the \(xy\)-coordinate system has vertices at \((-2 , -3), (4, -3)\) and \((28, 7),\) what is the area

by M7MBA » Thu Nov 05, 2020 8:31 am

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If a triangle in the \(xy\)-coordinate system has vertices at \((-2 , -3), (4, -3)\) and \((28, 7),\) what is the area of the triangle?

A. 30
B. 36
C. 48
D. 60
E. 65

Answer: A

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Re: If a triangle in the \(xy\)-coordinate system has vertices at \((-2 , -3), (4, -3)\) and \((28, 7),\) what is the ar

by Scott@TargetTestPrep » Tue Nov 10, 2020 6:13 am
M7MBA wrote: ↑
Thu Nov 05, 2020 8:31 am
 If a triangle in the \(xy\)-coordinate system has vertices at \((-2 , -3), (4, -3)\) and \((28, 7),\) what is the area of the triangle?

A. 30
B. 36
C. 48
D. 60
E. 65

Answer: A

Solution:

Since (-2, -3) and (4, -3) are on a horizontal line, the base of the triangle is 4 - (-2) = 6. The height of the triangle is the vertical distance from (28, 7) to the extension of the base, i.e., from (28, 7) to (28, -3). Therefore, the height is 7 - (-3) = 10, and the area of the triangle is ½ x 6 x 10 = 30.

Answer: A

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