If x^2 + 10y^2 - 6xy – 2y + 1 = 0, what is the value of x?

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[GMAT math practice question]

If x^2 + 10y^2 - 6xy - 2y + 1 = 0, what is the value of x?

A. 0
B. 1
C. 2
D. 3
E. 4
Source: — Problem Solving |

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by Max@Math Revolution » Sun Jul 21, 2019 5:31 pm
=>

x^2 + 10y^2 - 6xy - 2y + 1 = 0
=> x^2-6xy+10y^2-2y+1=0
=> x^2-6xy+9y^2+y^2-2y+1=0
=>(x-3y)^2+(y-1)^2=0
=> x=3y and y=1

Thus, x = 3.
Therefore, the answer is D.
Answer: D