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Seven cars of seven different models are going to park in a row of seven side-by-side parking spots for an advertisement

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Seven cars of seven different models are going to park in a row of seven side-by-side parking spots for an advertisement

by VJesus12 » Mon Sep 21, 2020 7:20 am

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Seven cars of seven different models are going to park in a row of seven side-by-side parking spots for an advertisement. Model \(P\) and Model \(Q\) must park next to each other, and Model \(S\) must be somewhere to the right of Models \(P \& Q.\) How many possible configurations are there for the cars?

a) 600
b) 720
c) 1440
d) 4320
e) 4800

Answer: B

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Re: Seven cars of seven different models are going to park in a row of seven side-by-side parking spots for an advertise

by DHRJ007 » Mon Sep 21, 2020 7:37 am
assume P and Q as a single entity .
now 6 cars can be arranged in 6!2! ways.
and probability of S to come right or left of P and Q is equal.
So, total number of ways in which S comes right to P and Q is 6!2!/2
i.e 720
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