2 lines will not intercept when they are parallel i.e they will have the same slope but different intercept on the y-axis
$$Expres\sin g\ the\ given\ equation\ in\ terms\ of\ y=mx+c$$
$$4y=-3x+5$$
$$y=\frac{-3x}{4}+\frac{5}{4}$$
$$m\left(slope\right)=\frac{-3}{4}\ and\ y\ \left(intercept\right)=\frac{5}{4}$$
$$testing\ all\ available\ options$$
$$\left(A\right)=>y=\frac{-4}{3}x+\frac{5}{3};\ m=\frac{-4}{3}and\ y\ intercept\ =\frac{5}{3}$$ $$\left(C\right)=>y=\frac{-3}{5}x+1;\ m=\frac{-3}{5}and\ y\ intercept\ =1$$
$$\left(D\right)=>y=\frac{-3}{5}x+\frac{3}{5};\ m=\frac{-3}{5}and\ y\ intercept\ =\frac{3}{5}$$
$$\left(E\right)=>y=\frac{3}{4}x+\frac{5}{4};\ m=+\frac{3}{4}and\ y\ intercept\ =\frac{5}{4}$$
$$But\ for\ option\ B=>y=\frac{-3}{4}x+\frac{10}{4}$$
$$=>y=\frac{-3}{4}x+\frac{5}{2};\ m=\frac{-3}{4}and\ y\ intercept=\frac{5}{2}$$
$$This\ gives\ same\ slope\ but\ different\ y\ intercept\ compared\ with\ the\ equation\ provided\ $$
$$so\ it\ can\ never\ inter\sec t$$
$$Answer\ =\ B$$