Hi Gurus,
One question I came across in MGMAT free CAT test (I was not able to complete the test as it timed out in between
, just wanted to know if I did this question in the right way)
A set of students in a school appeared for driving test which consists of a written test and a practical test. A student gets license only if he passes both written and practical. 30% of those students who passed the written exam failed in the practical. Find out the total number of students who got the license?
1. Total number of students = 188
2. 20% of those who passed the practical exam failed the written exam.
My Solution:
Let those who passed written be W and those who passed the practical be P. Our aim is to find the fraction of students who will passed both Written and Practical
From the question
70% of those who passed written exam got the license (Given: 30% of those students who passed the written exam failed in the practical). So our aim is to find 0.7W
I drew a tabular form with the Written/Practical as columns and Passed/Failed as rows.
So Written-Passed = W, Practical Passed = P, Written Failed = Unknown, Practical Failed = 0.3W
1. Total students = 188
No chance of finding W or P with this alone.
2. Means 80% of those who passed practical got license.
So 0.8P = 0.7W or W = (8/7)*P
So Written Failed = 0.2P (fill in the table)
But cannot find W or P here.
Combining 1 & 2:
Written Passed + Written Failed + Practical Passed + Practical Failed = Total
W + 0.2P + P + 0.3W = 188
Also we have from 2 --> W = (8/7)*P
So we can solve for W and P.
Hence C is the answer.
PS:- There could be small variations in the question as I am recollecting it as the test has timed out
One question I came across in MGMAT free CAT test (I was not able to complete the test as it timed out in between
A set of students in a school appeared for driving test which consists of a written test and a practical test. A student gets license only if he passes both written and practical. 30% of those students who passed the written exam failed in the practical. Find out the total number of students who got the license?
1. Total number of students = 188
2. 20% of those who passed the practical exam failed the written exam.
My Solution:
Let those who passed written be W and those who passed the practical be P. Our aim is to find the fraction of students who will passed both Written and Practical
From the question
70% of those who passed written exam got the license (Given: 30% of those students who passed the written exam failed in the practical). So our aim is to find 0.7W
I drew a tabular form with the Written/Practical as columns and Passed/Failed as rows.
So Written-Passed = W, Practical Passed = P, Written Failed = Unknown, Practical Failed = 0.3W
1. Total students = 188
No chance of finding W or P with this alone.
2. Means 80% of those who passed practical got license.
So 0.8P = 0.7W or W = (8/7)*P
So Written Failed = 0.2P (fill in the table)
But cannot find W or P here.
Combining 1 & 2:
Written Passed + Written Failed + Practical Passed + Practical Failed = Total
W + 0.2P + P + 0.3W = 188
Also we have from 2 --> W = (8/7)*P
So we can solve for W and P.
Hence C is the answer.
PS:- There could be small variations in the question as I am recollecting it as the test has timed out














