BTGmoderatorDC wrote:$$If\ S\ =\ 1\ +\ \frac{1}{2^2}+\frac{1}{3^2}+\frac{1}{4^2}+\frac{1}{5^2}+\frac{1}{6^2}+\frac{1}{7^2}+\frac{1}{8^2}+\frac{1}{9^2}+\frac{1}{10^2},\ which\ of\ the\ following\ is\ true?$$
A. S > 3
B. S = 3
C. 2 < S < 3
D. S = 2
E. S < 2
BALLPARK.
After the first four terms, the values are so small that they can be ignored.
Approximate the sum of the first four terms:
$$If\ S\ ≈\ 1\ +\ \frac{1}{4}+\frac{1}{10}+\frac{1}{15} = \ 1\ +\ \frac{15}{60}+\frac{6}{60}+\frac{4}{60} = \ 1\ +\ \frac{25}{60}$$
The resulting sum indicates that S < 2.
The correct answer is
E.
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