Aishwarya1204 wrote:How long did it take Betty to drive nonstop on a trip from her home to Denver. Colorado?
1) If Betty's avg speed for the trip had been 1.5 times as fast, the trip would have taken 2 hours.
2) Betty's avg speed for the trip was 50 miles per hour.
Jim's explanation regarding rate and time being inversely related, is great (as usual). I'll just add a bit of algebra to the mix.
Target question:
What was Betty's travel time?
Let D = The distance driven
Let R = Betty's average speed
Since Time = Distance/Rate, we can re[phrase the target question. . .
Rephrased target question:
What is the value of D/R?
Statement 1: If Betty's avg speed for the trip had been 1.5 times as fast, the trip would have taken 2 hours.
The distance is still the same (D), but the rate is 1.5R
So, statement 1 tells us that D/1.5R = 2
Is this enough information to find the value of
D/R?
Sure, just take the equation D/1.5R = 2 and multiply both sides by 1.5 to get
D/R = 3
Since we're able to answer the
rephrased target question with certainty, statement 1 is SUFFICIENT
Statement 2: Betty's avg speed for the trip was 50 miles per hour.
This tells us that R=50
However, we cannot find the value of
D/R, since we don't know the value of D (distance)
So, statement 2 is NOT SUFFICIENT
Answer =
A
Cheers,
Brent
