Actually, no.sri_r wrote:I solved it as follows:
x^2-x<0
x(x-1)<0
=> x<0 and x-1<0
=> x<0 and x>1
Is this right?
Unless you made a typing mistake in the first red line, you are partially correct.
And the two red lines are exclusive solution, i.e. they do not hold simultaneously.
So, a better way to put them will be : either x > 0 and (x - 1) < 0 or x < 0 and (x - 1) > 0
Now, the first solution simplifies to : x > 0 and x < 1 ---> 0 < x < 1
And, the second solution simplifies to : x > 0 and x < 1 ---> This is not possible.
So the final solution is 0 < x < 1
