This can be solved with little imagination.
Let's take each statement one by one.
1) \(x > y\)
=> \(90 > x > y\)
Imagine x = 75 and y = 30; you would observe that PQ << SR. Even if x and y are close to each other, ensuring that x > y, we have PQ < SR. The answer is yes. Sufficient.
2) \(x+y > 90\)
Clearly insufficient. So, we have all the possible three cases: (1) x = y = 45. (2) x > y and (3) x < y. no unique answer. Insufficient.
The correct answer: A
Hope this helps!
-Jay
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