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How do you solve

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Source: — Problem Solving |

by DeepakR » Tue Feb 03, 2009 4:05 pm
2/y+4/y= (2+4)/y=6/y=3(given) hence y=6/3=2. Ans.) y=2
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by hrishikesh05 » Fri Feb 06, 2009 1:47 am
Y can also be equal to zero

2/y + 4/y = 3
2y + 4y = 3y^2
6y = 3y^2
2y=y^2
y^2 - 2y = 0
y(y-2)=0

y= 2 or 0
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by DanaJ » Fri Feb 06, 2009 1:53 am
Sorry, y cannot be zero, since 2/0 is not defined.
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