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Three friends rented a car for a week and divided the cost e

Expert replies
by alanforde800Maximus » Thu May 10, 2018 1:50 am

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Answers

A

B

C

D

E

Stats

Difficulty—

Three friends rented a car for a week and divided the cost equally. If a fourth friend had joined them and the cost had been divided equally among the 4 friends, then the cost to each of the original 3 friends would have been reduced by $15? What was the total cost of renting the car?

a) $60
b) $100
c) $140
d) $160
e) $180

Source: Question Pack 1.
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Source: — Problem Solving |

by GMATGuruNY » Thu May 10, 2018 2:33 am
alanforde800Maximus wrote:Three friends rented a car for a week and divided the cost equally. If a fourth friend had joined them and the cost had been divided equally among the 4 friends, then the cost to each of the original 3 friends would have been reduced by $15? What was the total cost of renting the car?

a) $60
b) $100
c) $140
d) $160
e) $180
We can PLUG IN THE ANSWERS, which represent the total cost.
When the correct answer is plugged in, increasing the number of friends from 3 to 4 will reduce the cost per person by $15.

Since the total cost is divided equally among 3 or 4 friends, the correct answer is almost certainly a multiple of 3 and 4.
An integer is divisible by 3 only if its digits sum to a multiple of 3.
Of the five answer choices, only A and E have digits that sum to a multiple of 3.

E: Total cost = 180
If 3 friends divide the total cost equally, the cost per person = 180/3 = 60.
If 4 friends divide the total cost equally, the cost per person = 180/4 = 45.
Decrease in the cost per person = 60-45 = 15.
Success!

The correct answer is E.
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by Brent@GMATPrepNow » Thu May 10, 2018 5:29 am
alanforde800Maximus wrote:Three friends rented a car for a week and divided the cost equally. If a fourth friend had joined them and the cost had been divided equally among the 4 friends, then the cost to each of the original 3 friends would have been reduced by $15? What was the total cost of renting the car?

a) $60
b) $100
c) $140
d) $160
e) $180
Let's start with a word equation: (cost per person with 4 friends) = (cost per person with 3 friends) - $15

Let T = the total cost of renting the car

So, cost per person with 4 friends = T/4
And cost per person with 3 friends = T/3

We can now take our word equation and fill in the missing parts to get: T/4 = T/3 - 15
To eliminate the fractions, multiply both sides by 12 to get: (12T/4) = 12(T/3 - 15)
Expand: 3T = 4T - 180
Solve: T = 180

Answer: E

Cheers,
Brent
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by swerve » Thu May 10, 2018 10:34 am
Let the initial cost for each of the three friends be x units.

Total cost = 3x units

No, a new guy came in them the cost per friend = 3x/4 units

Reduction in cost = x - 3x/4 = x/4. And x/4 = 15, hence x = 60.

Total cost = 3*60 = 180. Option E.

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by Scott@TargetTestPrep » Sun May 13, 2018 5:00 pm
alanforde800Maximus wrote:Three friends rented a car for a week and divided the cost equally. If a fourth friend had joined them and the cost had been divided equally among the 4 friends, then the cost to each of the original 3 friends would have been reduced by $15? What was the total cost of renting the car?

a) $60
b) $100
c) $140
d) $160
e) $180
We can let the cost of the rental = n and create the equation:

n/3 = n/4 + 15

Multiplying by 12, we have:

4n = 3n + 180

n = 180

Answer: E

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