BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
Vote for Target Test Prep, Newsweek Readers’ Choice Awards 2026
NEWSWEEK READERS’ CHOICE 2026

BIG NEWS! Target Test Prep has been nominated, and they’d love your vote!

TTP has worked incredibly hard to build the best test prep experience possible, and winning Newsweek’s 2026 Readers’ Choice Award for Best Test Prep would mean a lot to them. If TTP has helped you, they’d be incredibly grateful for your vote. You can vote once each day through September 9.

Vote for TTP
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

problem solving-

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Newbie | Next Rank: 10 Posts
Posts: 2
Joined: Sun Jun 23, 2013 6:37 am
by nguyenduong » Sat Aug 10, 2013 10:06 am
Nine highschool boys gather at the gym for a game of mini-volleyball. Three teams of 3 people
each will be created. How many ways are there to create these 3 teams?

(A)
27

(B)
51

(C)
90

(D)
175

(E)
280


anyone pls help solution.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
User avatar
Legendary Member
Posts: 643
Joined: Wed Aug 14, 2013 4:27 amFollowed by: 7 members
Thanked: 48 times

Combinatorics, GMAT Math

by vinay1983 » Wed Aug 28, 2013 8:55 am
nguyenduong wrote:Nine highschool boys gather at the gym for a game of mini-volleyball. Three teams of 3 people
each will be created. How many ways are there to create these 3 teams?

(A)
27

(B)
51

(C)
90

(D)
175

(E)
280


anyone pls help solution.
I am bumping this for an answer.

I feel it is A.

What is the source?and the OA?
You can, for example never foretell what any one man will do, but you can say with precision what an average number will be up to!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Master | Next Rank: 500 Posts
Posts: 283
Joined: Sun Jun 23, 2013 11:56 pmFollowed by: 26 members
Location: Bangalore, India
Thanked: 97 times
GMAT Score:750

by ganeshrkamath » Wed Aug 28, 2013 10:35 am
nguyenduong wrote:Nine highschool boys gather at the gym for a game of mini-volleyball. Three teams of 3 people
each will be created. How many ways are there to create these 3 teams?

(A) 27
(B) 51
(C) 90
(D) 175
(E) 280

anyone pls help solution.
Let the boys be abcdefghi
Total ways of arranging them = 9!
Now abc_def_ghi is the same as abc_def_gih
So taking care of arrangements within a group = 9!/(3!3!3!) = (9*8*7*6*5*4*3!)/(3!3!3!)
= (9*8*7*5*4)/(3!) = (3*4*7*5*4)
= 1680

Also abc_def_ghi is the same as def_ghi_abc
So taking care of arrangements of the groups = 1680/3!
= 1680/6 = 280

Choose E
Every job is a self-portrait of the person who did it. Autograph your work with excellence.

Kelley School of Business (Class of 2016)
GMAT Score: 750 V40 Q51 AWA 5 IR 8
https://www.beatthegmat.com/first-attemp ... tml#688494
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
GMAT Instructor
Posts: 15539
Joined: Tue May 25, 2010 12:04 pmFollowed by: 1906 members
Location: New York, NY
Thanked: 13060 times
GMAT Score:790

by GMATGuruNY » Wed Aug 28, 2013 10:49 am
nguyenduong wrote:Nine highschool boys gather at the gym for a game of mini-volleyball. Three teams of 3 people
each will be created. How many ways are there to create these 3 teams?

(A)
27

(B)
51

(C)
90

(D)
175

(E)
280
Approach 1:
Team A:
From the 9 boys, the number of ways to choose 3 = 9C3 = (9*8*7)/(3*2*1) = 84.
Team B:
From the remaining 6 boys, the number of ways to choose 3 = 6C3 = (6*5*4)/(3*2*1) = 20.
Team C:
From the remaining 3 boys, the number of ways to choose 3 = 3C3 = (3*2*1)/(3*2*1) = 1.
To combine the options for each team, we multiply:
84*20*1.
Since the ORDER of the teams doesn't matter -- ABC is the same 3 teams as BCA-- we divide by the number of ways the 3 teams can be ARRANGED (3!):
(84*20*1)/(3*2*1) = 280.

The correct answer is E.

Approach 2:
The first boy selected must be combined with a pair of boys formed from the other 8 boys.
From the other 8 boys, the number of ways to choose 2 = 8C2 = (8*7)/(2*1) = 28.
6 boys remain.
The next boy selected must be combined with a pair of boys formed from the other 5 boys.
From the other 5 boys, the number of ways to choose 2 = 5C2 = (5*4)/(2*1) = 10.
3 boys left.
The next boy selected must be combined with a pair of boys formed from the other 2 boys.
From the other 2 boys, the number of ways to choose 2 = 2C2 = (2*1)/(2*1) = 1.
To combine the options for each boy selected, we multiply:
28*10*1 = 280.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 643
Joined: Wed Aug 14, 2013 4:27 amFollowed by: 7 members
Thanked: 48 times

by vinay1983 » Wed Aug 28, 2013 9:27 pm
GMATGuruNY wrote:
nguyenduong wrote:Nine highschool boys gather at the gym for a game of mini-volleyball. Three teams of 3 people
each will be created. How many ways are there to create these 3 teams?

(A)
27

(B)
51

(C)
90

(D)
175

(E)
280
Approach 1:
Team A:
From the 9 boys, the number of ways to choose 3 = 9C3 = (9*8*7)/(3*2*1) = 84.
Team B:
From the remaining 6 boys, the number of ways to choose 3 = 6C3 = (6*5*4)/(3*2*1) = 20.
Team C:
From the remaining 3 boys, the number of ways to choose 3 = 3C3 = (3*2*1)/(3*2*1) = 1.
To combine the options for each team, we multiply:
84*20*1.
Since the ORDER of the teams doesn't matter -- ABC is the same 3 teams as BCA-- we divide by the number of ways the 3 teams can be ARRANGED (3!):
(84*20*1)/(3*2*1) = 280.

The correct answer is E.

I was halfway there. I could realise that it No repetition and order does not matter and I could arrive at 9C3, then I could predict that the teams could be arranged 3! ways, but I failed to apply step 2 and 3, which you have mentioned. Thank Mitch!
You can, for example never foretell what any one man will do, but you can say with precision what an average number will be up to!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1