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kaarthikvs
- Junior | Next Rank: 30 Posts
- Posts: 11
- Joined: Sun Dec 02, 2012 5:24 am
Statement 1: As x³ is an integer, x need not be an integer.kaarthikvs wrote:Is x and integer ?
1) x³ is an integer
2) 3x is an integer
Consider the following two scenarios,
- x = 1 ---> x and x³ both are integers
x = cube root of 2 ---> x is not an integer but x³ is
Statement 2: If 3x is an integer, x need not be an integer.
Consider the following two scenarios,
- x = 1 ---> x and 3x both are integers
x = 1/3 ---> x is not an integer but 3x is
1 and 2 Together: Let us assume 3x = I, where I is some integer.
So, x = I/3 ---> x³ = I³/27
As x³ is an integer and I is also an integer, I³ must be divisible by 27.
Hence, I is divisible by 3.
So, x is an integer.
The correct answer is C.












