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Your Answer
A
B
C
D
E
Global Stats
\(\Big(\dfrac{1}{2}\Big)^{−3}\Big(\dfrac{1}{4}\Big)^{−2}\Big(\dfrac{1}{16}\Big)^{−1}=\)
\((A) \quad\Big(\dfrac{1}{2}\Big)^{-48}\)
\((B) \quad\Big(\dfrac{1}{2}\Big)^{-11}\)
\((C) \quad\Big(\dfrac{1}{2}\Big)^{-6}\)
\((D) \quad\Big(\dfrac{1}{8}\Big)^{-11}\)
\((E) \quad\Big(\dfrac{1}{8}\Big)^{-6}\)
Answer: B
Source: Official Guide
\((A) \quad\Big(\dfrac{1}{2}\Big)^{-48}\)
\((B) \quad\Big(\dfrac{1}{2}\Big)^{-11}\)
\((C) \quad\Big(\dfrac{1}{2}\Big)^{-6}\)
\((D) \quad\Big(\dfrac{1}{8}\Big)^{-11}\)
\((E) \quad\Big(\dfrac{1}{8}\Big)^{-6}\)
Answer: B
Source: Official Guide
