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There are enough available spaces on a school team to select at most 1/3

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There are enough available spaces on a school team to select at most 1/3

by BTGModeratorVI » Mon Sep 07, 2020 7:01 am

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There are enough available spaces on a school team to select at most 1/3 of the 50 students trying out for the team. What is the greatest number of students that could be rejected while still filling all available spaces for the team?

(A) 16
(B) 17
(C) 33
(D) 34
(E) 35

Answer: D
Source: Manhattan prep
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Re: There are enough available spaces on a school team to select at most 1/3

by Brent@GMATPrepNow » Wed Sep 09, 2020 6:18 am
BTGModeratorVI wrote: ↑
Mon Sep 07, 2020 7:01 am
 There are enough available spaces on a school team to select at most 1/3 of the 50 students trying out for the team. What is the greatest number of students that could be rejected while still filling all available spaces for the team?

(A) 16
(B) 17
(C) 33
(D) 34
(E) 35

Answer: D
Source: Manhattan prep
1/3 of 50 = (1/3)(50) = 50/3 = 16 2/3
Since the number of available spaces cannot be greater than 16 2/3, there must be 16 available spaces.
So, 16 students (among the original 50 students) can be selected to join the team, which means the other 34 students must be rejected.

Answer: D

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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