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Angle ACB = Angle POQ

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Angle ACB = Angle POQ

by sanju09 » Fri Jul 23, 2010 6:39 am
Radius of circle center O is 3 times the radius of circle center C.

Angle ACB = Angle POQ

If the shaded area of circle C is 2 then what is the area of the shaded part of circle O?
A. 6
B. 12
C. 18
D. 36
E. 72

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by selango » Fri Jul 23, 2010 6:43 am
OP=3AC

Area of ACB=Angle/360*pi*(AC)^2=2


Area of POQ= Angle/360/*pi*(OP)^2

Angle/360*pi*(3AC)^2

Angle/360*pi*(AC)^2 * 9=2*9

18

Pick C
Last edited by selango on Fri Jul 23, 2010 6:53 am, edited 1 time in total.
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by kvcpk » Fri Jul 23, 2010 6:44 am
r2 = 3r1

area of sector = angle/360 * pi *r^2
area of small shaded region = angle/360 * pi * r1^2 = 2
area of large shaded region = angle/360 * pi * r2^2

angle/360 * pi * r2^2
=angle/360 * pi *9 r1^2
=9*2 = 18
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