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The figure shows that OABC is a parallelogram. What is the equation of the line passing through A and C?

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by Max@Math Revolution » Mon Jan 13, 2020 12:14 am
[GMAT math practice question]
1.13PS.png
The figure shows that OABC is a parallelogram. What is the equation of the line passing through A and C?

A. y = 1/10x + 3/10
B. y = 5/11x + 20/11
C. y = 5/12x + 3/12
D. y = 1/13x + 3/13
E. y = 5/14x + 3/14
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Re: The figure shows that OABC is a parallelogram. What is the equation of the line passing through A and C?

by Max@Math Revolution » Wed Jan 15, 2020 12:19 am
=>


Since AB = CO = 4, we have point C(-4, 0).

Then the slope of the line AC is (5 - 0) / (7 - (-4)) = 5/11.
The equation of the line AC is y - 0 = (5/11)(x - (-4)) or y = (5/11)x + 20/11.

Therefore, B is the answer.
Answer: B
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