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by pepeprepa » Thu Aug 14, 2008 10:44 am
Indeed, I found that they are all false.
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by Vignesh.4384 » Thu Aug 14, 2008 10:51 am
IMO A
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by anju » Thu Aug 14, 2008 10:58 am
Hi, I do not know how to solve this. Here is where i got stuck? Not sure how to approach after this. Can someone help?

Avg = 150K
median = 130K
Means there are 7 values which are 130K or less and 8th value is 130K.
how to approach after this?
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by pepeprepa » Thu Aug 14, 2008 11:01 am
Vignesh you may be right, anyway I is true because
If the less expensive houses were all at 130
We have 130*8=1040
The total of the last 7 most expensive houses is 15*150-1040=1210
And the 7 houses cannot all be under 165 to go to 1210
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by Vignesh.4384 » Thu Aug 14, 2008 11:03 am
pepeprepa wrote:Indeed, I found that they are all false.
pepeprepa,

consider this worst case scenario.
14 houses are sold for 130000. So the 15th house should be more than 150000.

if even 1 house id going to be lesser than 130000 then the upper limit is going to increase.

wel and 1 last thing 130000 cant be the min value cos it is the median ..
So A has to be true isnt it ?

I hope u can understand what i am trying to say
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by anju » Thu Aug 14, 2008 11:06 am
got it, thanks....
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by priyankamishra11 » Thu Aug 14, 2008 1:10 pm
Thanks guys.. Indeed A is the answer but can you tell me why its answer is not E because 130,000 is median, So there must be at least one house which is sold less than 130,000.. isn't it ?
130,000 could not be the min. value
that makes 3rd statement correct.. am i doing something wrong?
Any explanations?
Regards,
Priyanka
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by Stuart@KaplanGMAT » Thu Aug 14, 2008 1:23 pm
priyankamishra11 wrote:Thanks guys.. Indeed A is the answer but can you tell me why its answer is not E because 130,000 is median, So there must be at least one house which is sold less than 130,000.. isn't it ?
130,000 could not be the min. value
that makes 3rd statement correct.. am i doing something wrong?
Any explanations?
The median is the middle term in the set. It's also possible that the median is the lowest term in the set.

For example, the set:

{130, 130, 130, 130, 130, 130, 130, 130, 130, 130, 190, 190, 190, 190, 190}

has 15 terms, a median of 130 and a mean of 150.

So the lowest number in any set must be less than OR equal to the median.
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by priyankamishra11 » Fri Aug 15, 2008 4:43 am
Thanks Stuart, I got it.
Regards,
Priyanka
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