The average of m, n, and p is q and the average of q and r is s. Which of the following is r in terms of m, n, p and s?
$$A.\ \frac{6s-m+n+p}{3}$$
$$B.\ \frac{6s-m-n-p}{3}$$
$$C.\ \frac{2s-m-n-p}{3}$$
$$D.\ \frac{s+m+n+p}{2}$$
$$E.\ 2s-m+n+p$$
The OA is B.
I solved this PS question as follow,
We are given that the average of m, n, and p is q and the average of q and r is s. Thus:
q = (m + n + p)/3
AND
s = (q + r)/2
2s = q + r
r = 2s - q
We can substitute (m + n + p)/3 for q into the second equation and we have:
r = 2s - (m + n + p)/3 = 6s/3 - (m + n + p)/3 = (6s - m - n -p)/3.
Is there a strategic approach to this question? Can any experts help, please? Thanks
$$A.\ \frac{6s-m+n+p}{3}$$
$$B.\ \frac{6s-m-n-p}{3}$$
$$C.\ \frac{2s-m-n-p}{3}$$
$$D.\ \frac{s+m+n+p}{2}$$
$$E.\ 2s-m+n+p$$
The OA is B.
I solved this PS question as follow,
We are given that the average of m, n, and p is q and the average of q and r is s. Thus:
q = (m + n + p)/3
AND
s = (q + r)/2
2s = q + r
r = 2s - q
We can substitute (m + n + p)/3 for q into the second equation and we have:
r = 2s - (m + n + p)/3 = 6s/3 - (m + n + p)/3 = (6s - m - n -p)/3.
Is there a strategic approach to this question? Can any experts help, please? Thanks
