Deviant Set

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Deviant Set

by kanha81 » Mon May 11, 2009 7:47 am
If Q is a set of consecutive integers, what is the standard deviation of Q?

(1) Set Q contains 21 terms.
(2) The median of set Q is 20.
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by tdadic84 » Mon May 11, 2009 9:17 am
IMO D....since we know they are consecutive, we know the SD...

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Re: Deviant Set

by California4jx » Mon May 11, 2009 9:59 am
kanha81 wrote:If Q is a set of consecutive integers, what is the standard deviation of Q?

(1) Set Q contains 21 terms.
(2) The median of set Q is 20.
is B the answer ? - explanation to follow after OA ?

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by Ian Stewart » Mon May 11, 2009 6:57 pm
From Statement 1, we know we have a set of 21 consecutive integers, so we know the distances between all elements of the set, and can therefore find the standard deviation.

From Statement 2, we don't have any idea how many elements there are. If there are only three elements, the standard deviation will be smaller than if there are seven elements (if there are three elements, the standard deviation is less than one, whereas if there are seven, the standard deviation is exactly 2), because in a larger set of consecutive integers, you'll have more elements which are far from the mean.

A.
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by cubicle_bound_misfit » Mon May 11, 2009 7:53 pm
Hi Ian,

This may be really stupid but if we don't know about anything about set of 21 integers how come their standard deviation could be measured?

suppose, it is a set of 21 negative integers or a set of 21 positive integers

lets say ,

-42, -43 ..... -22 etc and 100, 101........121 etc

how come both the series will have equal SD?

so if we get two different SD's then stmt 1 is insufficient ???

Please help.

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by Ian Stewart » Mon May 11, 2009 8:28 pm
cubicle_bound_misfit wrote:Hi Ian,

This may be really stupid but if we don't know about anything about set of 21 integers how come their standard deviation could be measured?

suppose, it is a set of 21 negative integers or a set of 21 positive integers
Remember what we use to calculate the standard deviation: the distance from each number to the average. I'll illustrate with an example - rather than use 21 consecutive integers, I'll just use seven for simplicity. Say you have this set:

0, 1, 2, 3, 4, 5, 6

The average of this set is 3. Now, to find the standard deviation, we first find how far each element is from the average, by subtracting (and making the result positive). Starting from 0, the distances from each element to the average (3) are:

3, 2, 1, 0, 1, 2, 3

These distances then go into the standard deviation formula, which you don't need to know in detail for the GMAT - and to save time, you'd definitely not want to go any further with the calculation. (Though if you want to know the calculation, you first square each distance, to get: 9, 4, 1, 0, 1, 4, 9; you then average this set to get (9+4+1+0+1+4+9)/7 = 28/7 = 4; and finally you take the square root to get 2).

Notice that it's the distances between elements in the set that matters here, and not the elements themselves. If we take a different set of seven consecutive integers, say:

990, 991, 992, 993, 994, 995, 996

then the average is 993, and the distances are again:

3, 2, 1, 0, 1, 2, 3

So plugging these distances into the standard deviation formula, we'll get the same answer as we got with the set {0,1,2,3,4,5,6}, since the distances are identical. The same would happen with a set of seven consecutive negative integers, or any other set of seven consecutive integers.

The upshot is this: whenever you know all of the distances between elements in a set, you can find the standard deviation. You don't actually need to know how large or small the elements are; you only need to know how they are separated. Every set of seven consecutive integers will have the same standard deviation, for example.
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by kanha81 » Tue May 12, 2009 9:00 am
Ian Stewart wrote:
cubicle_bound_misfit wrote:Hi Ian,

This may be really stupid but if we don't know about anything about set of 21 integers how come their standard deviation could be measured?

suppose, it is a set of 21 negative integers or a set of 21 positive integers
Remember what we use to calculate the standard deviation: the distance from each number to the average. I'll illustrate with an example - rather than use 21 consecutive integers, I'll just use seven for simplicity. Say you have this set:

0, 1, 2, 3, 4, 5, 6

The average of this set is 3. Now, to find the standard deviation, we first find how far each element is from the average, by subtracting (and making the result positive). Starting from 0, the distances from each element to the average (3) are:

3, 2, 1, 0, 1, 2, 3

These distances then go into the standard deviation formula, which you don't need to know in detail for the GMAT - and to save time, you'd definitely not want to go any further with the calculation. (Though if you want to know the calculation, you first square each distance, to get: 9, 4, 1, 0, 1, 4, 9; you then average this set to get (9+4+1+0+1+4+9)/7 = 28/7 = 4; and finally you take the square root to get 2).

Notice that it's the distances between elements in the set that matters here, and not the elements themselves. If we take a different set of seven consecutive integers, say:

990, 991, 992, 993, 994, 995, 996

then the average is 993, and the distances are again:

3, 2, 1, 0, 1, 2, 3

So plugging these distances into the standard deviation formula, we'll get the same answer as we got with the set {0,1,2,3,4,5,6}, since the distances are identical. The same would happen with a set of seven consecutive negative integers, or any other set of seven consecutive integers.

The upshot is this: whenever you know all of the distances between elements in a set, you can find the standard deviation. You don't actually need to know how large or small the elements are; you only need to know how they are separated. Every set of seven consecutive integers will have the same standard deviation, for example.
Beautifully explained Ian!
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by cubicle_bound_misfit » Tue May 12, 2009 10:36 am
Ian,

Another of my countless kudos.
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by California4jx » Tue May 12, 2009 2:21 pm
cubicle_bound_misfit wrote:
their standard deviation could be measured?
Ian .. THANKS .... !

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by [email protected] » Thu Nov 29, 2012 3:37 pm
would it matter if Set Q contained an even number of terms, i.e. 20. Average could be either x-1/2, or x + 1/2, depending on whether upper limit of set is x+9 or x+10