Is \(x > y?\)
(1) \(x - y - 1 > 0\)
(2) \(x - y + 1 > 0\)
[spoiler]OA=A[/spoiler]
Source: Magoosh
(1) \(x - y - 1 > 0\)
(2) \(x - y + 1 > 0\)
[spoiler]OA=A[/spoiler]
Source: Magoosh
If \(x > y\), \(x -y > 0\). Or the difference between x and y is positive.M7MBA wrote:Is \(x > y?\)
(1) \(x - y - 1 > 0\)
(2) \(x - y + 1 > 0\)
[spoiler]OA=A[/spoiler]
Source: Magoosh
Let's take each statement one by one.
(1) \(x - y - 1 > 0\)
\(x - y > 1\)
=> the difference between x and y is positive. The answer is yes. Sufficient.
(2) \(x - y + 1 > 0\)
\(x - y > -1\)
=> the difference between x and y can be positive, zero or negative. No unique answer. Insufficient.
The correct answer: A
Hope this helps!
-Jay
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