If sq rt (3-2x) = sq rt (2x) + 1, then 4x^2=
A. 1
B. 4
C. 2 - 2x
D. 4x - 2
E. 6x - 1
Source: OG 12
OA after some discussion.
A. 1
B. 4
C. 2 - 2x
D. 4x - 2
E. 6x - 1
Source: OG 12
OA after some discussion.
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Since none of the answer choices contains a √, we need to perform algebra that will clear all the √ symbols:chendawg wrote:If sq rt (3-2x) = sq rt (2x) + 1, then 4x^2=
A. 1
B. 4
C. 2 - 2x
D. 4x - 2
E. 6x - 1
Source: OG 12
OA after some discussion.
√(3-2x) - √2x = 1; square both sideschendawg wrote:If sq rt (3-2x) = sq rt (2x) + 1, then 4x^2=
A. 1
B. 4
C. 2 - 2x
D. 4x - 2
E. 6x - 1
Source: OG 12
OA after some discussion.
Squaring both sides of the equation, we have:chendawg wrote:If sq rt (3-2x) = sq rt (2x) + 1, then 4x^2=
A. 1
B. 4
C. 2 - 2x
D. 4x - 2
E. 6x - 1



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