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divisibility

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divisibility

by mav800rick » Thu May 29, 2008 4:29 pm
How many integers from 0 to 50, inclusive, have a remainder of 1 when divided by 3 ?
A. 15
B. 16
C. 17
D. 18
E. 19

-Simple question....OA is (C). i am sure its B.

any thoughts?
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by egybs » Thu May 29, 2008 4:36 pm
It takes 30 seconds to write out all the possibilities:

1,4,7,10,13,16,19,22,25,28,31,34,37,40,43,46,49

Count 'em up and you got 17. Answer is C.
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by zacharyz » Thu May 29, 2008 7:36 pm
Maybe forgot the 1?
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by netigen » Thu May 29, 2008 9:34 pm
No need to write the possibilities:

1. first multiple of 3 = 0
2. last multiple of 3 = 48

total multiples from 0 to 50 = 17 = our answer
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by getneonow » Thu May 29, 2008 10:08 pm
The numbers are represented by 3k +1 where k = 0,1,2....

the max value K can take is k = 16 for the number 49

so from 0 to 16 there would be 17 numbers ..which is the reqd answer
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