Hi,
My approach is as follows:-
for y = 3x+2 to contain (r,s) (r,s) should satisfy the line y = 3x+2 i.e.
s = 3r+2.
1) Put r = 0, (2-s)(9-s) = 0 => s has two values, not sufficient
2) Put r = 0, (-6-s)(2-s) = 0 => s has two values, not sufficient
However, from 1 and 2 we get s = 2, and r =0 which satisfies the equation
s = 3r + 2.
Hence, C.
Is my approach correct. Can someone suggest an alternate approach.
Thanks
Amit
My approach is as follows:-
for y = 3x+2 to contain (r,s) (r,s) should satisfy the line y = 3x+2 i.e.
s = 3r+2.
1) Put r = 0, (2-s)(9-s) = 0 => s has two values, not sufficient
2) Put r = 0, (-6-s)(2-s) = 0 => s has two values, not sufficient
However, from 1 and 2 we get s = 2, and r =0 which satisfies the equation
s = 3r + 2.
Hence, C.
Is my approach correct. Can someone suggest an alternate approach.
Thanks
Amit
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