Hi,
The answer is D) but can anyone give me explanation?
Thanks!
test23 3 13
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okay here you go:
The only number which satisfies the given condition is : 101
and a(n)=a(1)+(n-1)d
199=100+(n-1)d
==> n=100 terms
Probability of selecting 1 number out of 100 numbers is 1/100 hence D
R
The only number which satisfies the given condition is : 101
and a(n)=a(1)+(n-1)d
199=100+(n-1)d
==> n=100 terms
Probability of selecting 1 number out of 100 numbers is 1/100 hence D
R
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Since we have to pick a number between 100 and 199 both inclusive...it is imperative that the hundreds digit is always 1....for the hundreds and last digit always to be 1 more than the middle digit...the last digit has to be 1 and the middle digit 0
There is only 1 such number i.e. 101
So probability = 1/100
There is only 1 such number i.e. 101
So probability = 1/100