For the second statment:
I multiplied both sides by 10 hence I got 1^n-1 > 1 and because one is equivilant to 1^1 I dropped the 1's and was left with:
n-1 > 1 --> n > 2 which is the same as the first statement
Is this the right way of doing it or was it a fluke? can I do this question this way instead of like the back of the book by trying 1 and 2 first.
I multiplied both sides by 10 hence I got 1^n-1 > 1 and because one is equivilant to 1^1 I dropped the 1's and was left with:
n-1 > 1 --> n > 2 which is the same as the first statement
Is this the right way of doing it or was it a fluke? can I do this question this way instead of like the back of the book by trying 1 and 2 first.
