Data Sufficiency

Is x^2 + y^2 > 6

(1) (x+y)^2 > 6
(2) xy = 2

IMO E!

exceptional bubli... post your approach

This time when I was scrolling down the screen I kept my fingers crossed as I was afraid to see "Sorry Pranay" again .

Coming to the question,

Option 1:
Consider X,Y as (1,3), (1, 1.6), (-4,1) this is INSUFFICIENT.

Option 2:
Consider X,Y as (1,2), (4, .5) this is INSUFFICIENT.

Consider both, which is something similar to B. INSUFFICIENT.

Now the obvious question you would get after going through the X,Y values in option 1 is why and how 1.6?

To answer that, given from 1, (x+y)^2 > 6 => (x+y) > sqrt(6) which is close to 2.5
Thus, we can rewrite option 1 as, (x+y) > 2.5

Thus E.

st 1: x^2+y^2+2xy >6 here x and y can be positive or negative so not suff.
st 2: xy=2 not suff
taken together st 1 becomes x^2+y^2+4>6
x^2+y^2>4, it can eb equal to 5 or 10 or anything.
so E.