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by hpgmat » Tue Dec 08, 2009 8:01 pm
if x and y are integers greather than 1 , is x a multiple of y?

1) 3(y^2) + 7y = x

2) x^2- x is multiple of y

my approach :

x multiple of y translates to : is X = A Y ??

1) Y (3Y+7) = X ....> now x is written as AY ( with (3Y + 7) being A)

2) x^2 - x = B Y ....> x (x-1) = B Y ...> X = (B/(x-1)) Y ....> X is written as AY ( with B/(x-1) being A
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Source: — Data Sufficiency |
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by bou_k » Wed Dec 09, 2009 1:58 am
you have a problem B/(x-1)) is not an integer in general so the ans is only A)
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by adamsmith2009 » Wed Dec 09, 2009 8:33 am
A) Not sufficient. X could be 3 which would make Y= 34 or X could be 2 which would make Y= 20.

B) Sufficient. x(x-1) = multiple of Y

So if x is 3 y is a multiple of 6. Therefore the minimum number y could be would be 6. So x can't be a multiple of y.
If x is 5 y is a multiple of 20. Therefore the minimum number y could be would be 20. So x can't be a multiple of y. X is always less than Y.

What's the OA?
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by November Rain » Wed Dec 09, 2009 10:16 am
Hi
I think it's E. Could you please let us know the OA?

A is insufficient - If you add two numbers multiple of Y and theresult is a multiple of X doesn't mean that Y is a multiple of X on its own.

B is also insufficient - It can be rephrased into x(x-1) is a multiple of Y. However, the number that can allow Y to become multiple of x(x-1) might be X-1 or X. So, also insufficient.

Both statements together don't seem to add any new information to each other. So, its E.

Could anyone confirm the OA?
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by hpgmat » Wed Dec 09, 2009 11:55 am
adamsmith2009 wrote:A) Not sufficient. X could be 3 which would make Y= 34 or X could be 2 which would make Y= 20.

B) Sufficient. x(x-1) = multiple of Y

So if x is 3 y is a multiple of 6. Therefore the minimum number y could be would be 6. So x can't be a multiple of y.
If x is 5 y is a multiple of 20. Therefore the minimum number y could be would be 20. So x can't be a multiple of y. X is always less than Y.

What's the OA?
you are thinking x factor of y . question is saying x multiple of y
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