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median?

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by earth@work » Fri Feb 13, 2009 10:20 pm
What is the median number of employees assigned per project for the projects at Company Z?
(1) 25 percent of the projects at Company Z have 4 or more employees assigned to each project.
(2) 35 percent of the projects at Company Z have 2 or fewer employees assigned to each project.
Ans: [spoiler]shows A & E some error in answer[/spoiler]
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by Bidisha800 » Fri Feb 13, 2009 10:53 pm
(E)

35% is <= 2

25%>= 4

if there are 100 projects average of 50th and 51st in ascending order would be >=4 but not sure exactly how much.
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by raghu_g_p » Sat Feb 14, 2009 1:57 am
I will go with C.

I and II insuff.

Taken together, 40% of the projects have exactly 3 members in the project. So

35%(with 2 or less), 40%(with 3), 25%(with 4 0r more).
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by Uri » Sat Feb 14, 2009 2:45 am
IMO (C) i fully agree with the explanation of raghu_g_p.
could you please specify the source of this problem?
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by naaga » Sat Feb 14, 2009 7:41 am
what is OA
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by awesomeusername » Sat Feb 14, 2009 9:29 am
If 25% have 4 or more
and 35% have 2 or less
that implies that the remaining 40% have exactly 3 people.
If we have 100 projects altogether, the first 35 will have 2 or less people, the next 40 projects will have 3 people, and the last 25 projects will have 4 or more people. We know that the median is the average number of people between the 50th and 51st project. The 50th has 3 people, and the 51st has 3 people, so the median is 3. So the answer is C.
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by earth@work » Sat Feb 14, 2009 10:26 am
thanks, i guess C should be correct... as we have 3 groups===> 2-; x; 4+ therefore x will be between 2 & 4 which is 3, hence the median!
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