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A list of consecutive integers

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by talaangoshtari » Sat Aug 06, 2016 9:47 am
R is a list of 15 consecutive integers,and T is a list of 21 consecutive integers. The median of the integers in list R is equal to the least integer in list T. If the two lists are combined into one list of 36 integers, how many different integers are on the combined list?

A. 25
B. 27
C. 28
D. 32
E. 36
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by DavidG@VeritasPrep » Sat Aug 06, 2016 11:24 am
talaangoshtari wrote:R is a list of 15 consecutive integers,and T is a list of 21 consecutive integers. The median of the integers in list R is equal to the least integer in list T. If the two lists are combined into one list of 36 integers, how many different integers are on the combined list?

A. 25
B. 27
C. 28
D. 32
E. 36
Try it with simple numbers. Set R: {1 - 15} The Median is 8. Set T: {8 - 28} So the combined list will contain every integer between 1 and 28, inclusive. Answer is C.
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by Matt@VeritasPrep » Fri Aug 19, 2016 2:37 am
Another idea:

R has 7 numbers smaller than its median. None of these will be in list T. The rest will be.

T has 21 numbers.

So we've got 7 + 21, or 28 numbers.
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