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If k and x are positive integers and x is divisible by 6

Expert replies
Source: — Problem Solving |

by saurabhdhakad » Sat Aug 17, 2013 12:22 pm
Hi,
May be this approach can help to eliminate options:

Its given that x and k are Integers. Also x/6= Integer. Thus x= 6I
So expression becomes squareroot of 288*k*6I
i.e. 12*2* squareroot of 3*k*I

Thus k can be 3 and I can be k or 1.
This will eliminate all but not B.
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