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by sanju09 » Tue Nov 04, 2014 1:58 am
The larger interior angle of a parallelogram is 90° more than its smaller interior angle. What is the measure of the smaller interior angle of the parallelogram?
A. 90°
B. 75°
C. 60°
D. 45°
E. 30°


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by chetan86 » Tue Nov 04, 2014 7:42 am
sanju09 wrote:The larger interior angle of a parallelogram is 90° more than its smaller interior angle. What is the measure of the smaller interior angle of the parallelogram?
A. 90°
B. 75°
C. 60°
D. 45°
E. 30°


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In Parallelogram adjacent angles make 180°, while opposite angles are equal.
so, x+x+90°=180°
Ans: D. 45°
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by Mathsbuddy » Wed Nov 05, 2014 3:14 am
Let's use for convenience a parallelogram with a horizontal base and one obtuse angle directly above (vertically) the opposite acute angle. Now draw a line between these 2 angles to create 2 right angle triangles.
Each triangle will be isosceles, so the acute angle will be 90/2 - 45 degrees.
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