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If \(n\) is the product of all odd prime numbers less than \(16,\) how many factors does \(n\) have?

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Re: If \(n\) is the product of all odd prime numbers less than \(16,\) how many factors does \(n\) have?

by Scott@TargetTestPrep » Fri Feb 05, 2021 4:26 pm
M7MBA wrote: ↑
Sun Jan 24, 2021 2:14 pm
 If \(n\) is the product of all odd prime numbers less than \(16,\) how many factors does \(n\) have?

A. 5
B. 6
C. 16
D. 32
E. 64

Answer: D

Solution:

We see that n = 3^1 x 5^1 x 7^1 x 11^1 x 13^1, and thus n has (1 + 1) x (1 + 1) x (1 + 1) x (1 + 1) x (1 + 1) = 2^5 = 32 factors.

Answer: D

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