goyalsau wrote:alivapriyada wrote:goyalsau wrote:alivapriyada wrote:Machine A and Machine B can produce 1 widget in 3 hours working together at their respective constant rates. If Machine A's speed were doubled, the two machines could produce 1 widget in 2 hours working together at their respective rates. How many hours does it currently take Machine A to produce 1 widget on its own?
1/2
2
3
5
6
I don't know much explanation about this one i did it by option first 3 are out because in combination it t 3 hour so it will be more than that, and in 5 and 6.
6 because they both works at the same rate so it will take 6 hours
i know this is not the best explanation in the world but i really don't know how to explain it, so i am sure somebody please explain it further with the method so it will be very help full for me..
Is it 6.
Yes it is.
could you Please explain in detail...
Let X/h be machine A's constant rate and Y/h be machine B's constant rate and w stand for widget.
It follows that:
X/h + Y/h = 1/3w
doubling machine A's rate yields: 2X/h and now the two machines combined produce 1/2w per hour:
2X/h + Y/h = 1/2w
now substitute from equation one:
Y/h= 1/3w-X/h
and plug it into eq 2, which yields:
2X/h + (1/3w-X/h) = 1/2w
by rearranging:
X/h = 1/6w
Solving for w, which is 6.
Hope this helps.
