BTGmoderatorDC wrote: ↑Fri Apr 10, 2020 4:30 pm
A feed store sells two varieties of birdseed: Brand A, which is 40% millet and 60% sunflower, and Brand B, which is 65% millet and 35% safflower. If a customer purchases a mix of the two types of birdseed that is 50% millet, what percent of the mix is Brand A?
A) 40%
B) 45%
C) 50 %
D) 60 %
E) 55 %
OA
D
Source: Manhattan Prep
Say the customer purchases x kgs of Brand A and y kgs of Brand B.
Thus,
the weight of millet = 40% of x + 65% of y = 0.4x + 0.65y
the weight of sunflower = 60% of x + 35% of y = 0.6x + 0.35y
Since millet is 50% of the mixture, i.e., (x + y) kgs.
=> 0.4x + 0.65y = 0.6x + 0.35y
x = 1.5y
Total weight of the mixture = x + y = 1.5y + y = 2.5y kgs
Thus, the proportion of Brand A = [x/(x + y)]*100% = [1.5y/(2.5y)]*100% = 60%
The correct answer:
D
Hope this helps!
-Jay
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