Answer is: B
statement 2 tells us that z = 0.
value of xyz
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Source: Beat The GMAT — Data Sufficiency |
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Tryingmybest
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IMo E
1. y!=6 and x! > 720
Insufficient , we dont know anything about Z and X could take multiple values.
2. z is the least even integer greater than -1
Least even integer greater than -1 is 2
Zero is positive in GMAT world( Please correct me if I am wrong)
Combining we dont have a definite value for X
SO E
1. y!=6 and x! > 720
Insufficient , we dont know anything about Z and X could take multiple values.
2. z is the least even integer greater than -1
Least even integer greater than -1 is 2
Zero is positive in GMAT world( Please correct me if I am wrong)
Combining we dont have a definite value for X
SO E
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Mustang
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Tryingmybest wrote:IMo E
1. y!=6 and x! > 720
Insufficient , we dont know anything about Z and X could take multiple values.
2. z is the least even integer greater than -1
Least even integer greater than -1 is 2
Zero is positive in GMAT world( Please correct me if I am wrong)
Combining we dont have a definite value for X
SO E
Zero is neither positive nor negative. zero is definately even everywhere. So I think answer is B












