How many different combinations of outcomes can you make by rolling four standard (6-sided) dice if the order of the dice does not matter?
OA not available
OA not available
Not quite sure of my answer, anyways.
We have 6 different possibilities here, (Note: Order does not matter)
All 6 different - 1 Possibility
All 6 same - 6 Possibilities.
2 Same - 4 different
Pick 4 different numbers from 6 - 6C4 (and) of the remaining 2 any 1 will be repeated twice, So 2*6C4 = 30
3 Same - 3 Different.
3 different from 6 - 6C3 ways. Of the other 3 any 1 can be repeated 3 times. So, 3*6C3 = 60
4 Same - 2 Different.
2 different from 6 - 6C2 ways. Of the remaining 4, any 1 can be repeated 4 time. So, 4*6C2 = 60
5 Same - 1 different.
1 from 6 numbers. 6C1 ways. And of the remaining 5, any 1 can be repeated 5 times. So, 5*6C1 = 30.
In total we have, 1+6+30+60+60+30 = 187.
Let me try for 4 again
